21x^2-5x+2=6

Solution for 21x^2-5x+2=6 equation:

Simplifying
21x2 + -5x + 2 = 6

Reorder the terms:
2 + -5x + 21x2 = 6

Solving
2 + -5x + 21x2 = 6

Solving for variable 'x'.

Reorder the terms:
2 + -6 + -5x + 21x2 = 6 + -6

Combine like terms: 2 + -6 = -4
-4 + -5x + 21x2 = 6 + -6

Combine like terms: 6 + -6 = 0
-4 + -5x + 21x2 = 0

Factor a trinomial.
(-1 + -3x)(4 + -7x) = 0

Subproblem 1
Set the factor '(-1 + -3x)' equal to zero and attempt to solve:

Simplifying
-1 + -3x = 0

Solving
-1 + -3x = 0

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -3x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -3x = 0 + 1
-3x = 0 + 1

Combine like terms: 0 + 1 = 1
-3x = 1

Divide each side by '-3'.
x = -0.3333333333

Simplifying
x = -0.3333333333
Subproblem 2
Set the factor '(4 + -7x)' equal to zero and attempt to solve:

Simplifying
4 + -7x = 0

Solving
4 + -7x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -7x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -7x = 0 + -4
-7x = 0 + -4

Combine like terms: 0 + -4 = -4
-7x = -4

Divide each side by '-7'.
x = 0.5714285714

Simplifying
x = 0.5714285714
Solution
x = {-0.3333333333, 0.5714285714}